喝汽水问题

编程实现：

喝汽水，1瓶汽水1元，2个空瓶可以换一瓶汽水，

给20元，可以多少汽水。

#include <stdio.h> int main() { int drink = 20, cover = 20;//20个瓶子20个瓶盖 int sum = 20; while (cover != 1) { drink = cover; cover = drink / 2 + drink % 2; sum += drink / 2; } printf("%d", sum); }