程序设计与问题求解实验

题目

设计一个保存学生成绩信息的结构，包括学号、姓名、课程名、平时成绩、考试成绩、总评成绩。分别用函数实现以下功能：

输入n个学生的信息（平时和考试成绩）要求计算并输出学生的总分（平时２０％，考试８０％）并输出；输出总分最高和最低的学生信息。

代码

我是用动态链表来存储学生信息的！

#include <stdio.h> #include <stdlib.h> #include <assert.h> //#include <time.h> #define LEN sizeof(struct student) struct course { float pea,exam; }; struct student //声明结构体 { long num; char name[20]; float score; struct course Chi,Math,Eng; struct student *next; }; int n; //记录链表结构体数量 struct student *max,*min; //保存最高分与最低分同学的信息 struct student *creat(void) //建立关于学生的动态链表，并计算总成绩 { struct student *head; struct student *p1,*p2; n=0; p1=p2=(struct student * )malloc(LEN); printf("Please input student's ID and Name :\n"); scanf("%ld %s",&p1->num,&p1->name); head=NULL; while (p1->num!=0) { n=n+1; if (n==1)head=p1; else p2->next=p1; p2=p1; p1=(struct student * )malloc(LEN); printf("Please input student's ID and Name :\n"); scanf("%ld %s",&p1->num,&p1->name); } p2->next=NULL; return(head); } void input(struct student *head) { struct student *p; srand( (unsigned)time( NULL ) ); for(p=head;p!=NULL;p=p->next) { printf("Please input %s's common,exam score of Chinese:\n",p->name); //printf("%.0f\t%.0f\n",p->Chi.pea=rand()0,p->Chi.exam=rand()0); scanf("%f %f",&p->Chi.pea,&p->Chi.exam); printf("Please input %s's common,exam score of Math:\n",p->name); //printf("%.0f\t%.0f\n",p->Math.pea=rand()0,p->Math.exam=rand()0); scanf("%f %f",&p->Math.pea,&p->Math.exam); printf("Please input %s's common,exam score of English:\n",p->name); //printf("%.0f\t%.0f\n",p->Eng.pea=rand()0,p->Eng.exam=rand()0); scanf("%f %f",&p->Eng.pea,&p->Eng.exam); p->score=(p->Chi.pea+p->Math.pea+p->Eng.pea)*0.2 +(p->Chi.exam+p->Math.exam+p->Eng.exam)*0.8; //printf(" %f \n",p->score); } } void seek(struct student *head) //搜索总分最高和最低 { struct student *p; float Max,Min; Max=Min=head->score; for(p=head;p!=NULL;p=p->next) { if(p->score>=Max) { Max=p->score; max=p; } if(p->score<=Min) { Min=p->score; min=p; } } } void print () //输出总分最高和最低 { printf("\nThere are %d students in all.\n",n); printf("The information of the students with the highest total score is as follows :\n"); printf("%ld\t%s\t%.2f\n",max->num,max->name,max->score); printf("The information of the students with the lowest total score is as follows :\n"); printf("%ld\t%s\t%.2f\n",min->num,min->name,min->score); } int main ( ) //主函数 { struct student *head; head=creat(); input(head); seek(head); print(); system("pause"); return 0; }