接受前端数据进行转换！

需求

1.接受前端传递的数据转化为字典，后端使用参数去请求任意接口。 解决办法： json 中的 loads函数

For example

import json class GoodsListView(View): def get(self, request): ……… demo_str = '{"status": "ok"}' demo_json = json.loads(demo_str) print('type --------> %s' % type(demo_json)) print('demo_json --------> %s' % demo_json)

控制台输出：

type -----------> <class 'dict'> demo_json -----------> {'status': 'ok'} Process finished with exit code 0

loads这个函数当然没这么简单，它能将字符串中的整数、浮点数、嵌套字典、数组、布尔值、butes成功转化。

import json if __name__ == '__main__': # 整数+浮点+嵌套字典+数组 测试 demo_str = '{"status": {"number": 12322, "float": 12.21, "list": [1,2, "3"]}}' demo_json = json.loads(demo_str) print('type -----------> %s' % type(demo_json )) print('demo_json -----------> %s' % demo_json ) # if __name__ == '__main__': # 布尔值+空值 测试 # demo_str = '{"status1": true, "status2": false, "status3": null}' # demo_json = json.loads(demo_str) # print('type -----------> %s' % type(demo_json )) # print('demo_json -----------> %s' % demo_json )

控制台输出;

type -----------> <class 'dict'> demo_json-----------> {'status': {'number': 12322, 'float': 12.21, 'list': [1, 2, '3']}} Process finished with exit code 0 type -----------> <class 'dict'> demo_json-----------> {'status1': True, 'status2': False, 'status3': None} Process finished with exit code 0

就不多做赘叙了，给大家看看loads 的两段关键源码

elif nextchar == 'n' and string[idx:idx + 4] == 'null': return None, idx + 4 elif nextchar == 't' and string[idx:idx + 4] == 'true': return True, idx + 4 elif nextchar == 'f' and string[idx:idx + 5] == 'false': return False, idx + 5 **********************源码看懂关键字才有研究动力************************* *********************************************************************** elif nextchar == 'N' and string[idx:idx + 3] == 'NaN': return parse_constant('NaN'), idx + 3 elif nextchar == 'I' and string[idx:idx + 8] == 'Infinity': return parse_constant('Infinity'), idx + 8 elif nextchar == '-' and string[idx:idx + 9] == '-Infinity': return parse_constant('-Infinity'), idx + 9

Thank you for reading ！！！