LeetCode69 Sqrt(x)

题目：

       Implement int sqrt(int x).

       Compute and return the square root of x, where x is guaranteed to be a non-negative integer.

       Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.

       Example 1:

Input: 4 Output: 2

       Example 2:

Input: 8 Output: 2 Explanation: The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned. public class MySqrt { public static int mySqrt(int x) { if (x == 0){ return 0; } int left = 1; int right = Integer.MAX_VALUE; while (true) { int mid = left + (right - left) / 2; if (mid > x / mid) { right = mid - 1; } else { if (mid + 1 > x / (mid + 1)) return mid; left = mid + 1; } } } public static void main(String[] args) { System.out.println(mySqrt(125)); } }