地址 这道题很水 ，应该十分钟内就解决 。但是我的思路比较僵硬， 想用ｉｆ来判断星期几 ， 然后就发现ＷＡ了。然后换成用ｃｈａｒ数组来存字母 ， 在对天数做处理就过了。 第一次代码：
#include <iostream> #include <algorithm> #include <cmath> //#include <bits/stdc++.h> #include <vector> #include<cstdio> using namespace std; int main( ) { int t; cin >>t; while(t--){ long long year , month , date ; string s; cin >>year >>month >>date; cin >>s; long long year1 , month1 , date1 ; cin >>year1 >>month1 >>date1; long long sum = (year1 - year)*360 + (month1 - month)*30 + date1- date; if(sum<0) sum = -sum; if(sum%5==0) { cout<<s<<endl; } else if(sum%5==1){ if(s=="Monday") cout<<"Tuesday"<<endl; else if(s=="Tuesday") cout<<"Wednesday"<<endl; else if(s=="Wednesday") cout<<"Thursday"<<endl; else if(s=="Thursday") cout<<"Friday"<<endl; else { cout<<"Monday"<<endl; } } else if(sum%5==2){ if(s=="Monday") cout<<"Wednesday"<<endl; else if(s=="Tuesday") cout<<"Thursday"<<endl; else if(s=="Wednesday") cout<<"Friday"<<endl; else if(s=="Thursday") cout<<"Monday"<<endl; else { cout<<"Tuesday"<<endl; } } else if(sum%5==3){ if(s=="Monday") cout<<"Thursday"<<endl; else if(s=="Tuesday") cout<<"Friday"<<endl; else if(s=="Wednesday") cout<<"Monday"<<endl; else if(s=="Thursday") cout<<"Tuesday"<<endl; else { cout<<"Wednesday"<<endl; } } else if(sum%5==4){ if(s=="Monday") cout<<"Friday"<<endl; else if(s=="Tuesday") cout<<"Monday"<<endl; else if(s=="Wednesday") cout<<"Tuesday"<<endl; else if(s=="Thursday") cout<<"Wednesday"<<endl; else { cout<<"Thursday"<<endl; } } } return 0; } /**/第二次代码：
#include <iostream> #include <algorithm> #include <cmath> //#include <bits/stdc++.h> #include <vector> #include<cstdio> using namespace std; string daytable[] = { "Monday", "Tuesday", "Wednesday", "Thursday", "Friday" }; int main( ) { int t; cin >>t; for(int j=0;j<t;j++){ long long year , month , date ; string s; cin >>year >>month >>date; cin >>s; long long year1 , month1 , date1 ; cin >>year1 >>month1 >>date1; long long sum = (year1 - year)*360 + (month1 - month)*30 + date1- date; sum %=5; if(sum<0) sum +=5; int now =0; for(int i=0;i<5;i++){ if(daytable[i]==s){ now =i; break; } } cout<<daytable[(now + sum)%5]<<endl; } return 0; } /**/