使用Python简单的发送邮件

#来源忘了，就不贴链接地址了

#简单的python smtp发邮件代码

import smtplib from email.mime.text import MIMEText mailto_list=["123456789@qq.com","987654321@qq.com"] mail_host="smtp.qq.com" mail_user="123456789@qq.com" mail_pass="***************" mail_postfix="qq.com" def send_mail(to_list,sub,content):     '''     to_list:发给谁     sub:主题     content:内容     send_mail("aaa@126.com","sub","content")     '''     me=mail_user+"<"+mail_user+"@"+mail_postfix+">"     msg=MIMEText(content)     msg['Subject']=sub     msg['From']=me     msg['To']=";".join(to_list)     try:         s=smtplib.SMTP(port=465)         s.connect(mail_host)         s.login(mail_user,mail_pass)         s.sendmail(me, to_list,msg.as_string())         s.close()         return True     except Exception, e:         print str(e)         return False      if __name__ == '__main__':     sub="hello baby(python test mail)"     content="乔装打扮，不择手段"     if send_mail(mailto_list,sub,content):         print "发送成功"     else:         print "发送失败"      相关资源：python入门教程(PDF版)