关于这个游戏，我们完全可以用二维数组来实现，利用二维数组模拟出一个棋盘，比如board[ROW][COL]，其中ROW代表行数，COL代表列数。用函数来实现游戏中的各种行为，并判断每一次落子后的输赢，平局，还是未分出胜负继续进行游戏。 接下来看看实现的代码。
#include<stdio.h> #include<stdlib.h> #include<time.h> #include<string.h> #define ROW 3 //行 设定游戏规模 #define COL 3 //列 void menu(); void game(); void Initboard(char board[ROW][COL], int row, int col); //初始化棋盘 void Printboard(char board[ROW][COL], int row, int col); //打印棋盘 void palyer_move(char board[ROW][COL], int row, int col); //玩家下棋 void computer_move(char board[ROW][COL], int row, int col); //电脑下棋 char Judge(char board[ROW][COL], int row, int col); //判断输赢条件，玩家赢返回‘*’，电脑赢返回‘#’， //平局返回‘p’,游戏未分出胜负，返回‘c’ void menu() { printf("=====================\n"); printf("===== 1.play =====\n"); printf("===== 0.exit =====\n"); printf("=====================\n"); } void Printboard(char board[ROW][COL], int row, int col) { int i, j; for (i = 0; i < row; i++) { for (j = 0; j < col; j++) { printf(" %c ",board[i][j]); if (j <col - 1) { printf("|"); } } printf("\n"); for (j = 0; j < col; j++) { if (i < col - 1) { if ((j < row - 1)) printf("---|"); else printf("---"); } } printf("\n"); } } void Initboard(char board[ROW][COL], int row, int col) { memset(&board[0][0], ' ', row*col); } void palyer_move(char board[ROW][COL], int row, int col) { int x, y; while (1) { printf("输入要走的坐标:>"); scanf("%d%d", &x, &y); if (x >= 1 && x <= ROW && y >= 1 && y <= COL && board[x - 1][y - 1]==' ') { board[x - 1][y - 1] = '*'; break; } else printf("非法输入！"); } } void computer_move(char board[ROW][COL], int row, int col) { int x, y; while (1) { x = rand() % 3 + 1; y = rand() % 3 + 1; if (x >= 1 && x <= ROW && y >= 1 && y <= COL && board[x - 1][y - 1] == ' ') { board[x - 1][y - 1] = '#'; break; } } } char Judge(char board[ROW][COL], int row, int col) { int i, j; int count2 = 0; int count4 = 0; int count5 = 0; int count6 = 0; int count7 = 0; int k = row - 1; int k1 = row - 1; //判断玩家赢条件1 for (i = 0; i < row; i++) { for (j = 0; j < col; j++) { if ((board[i][j]) == '*' && (i == j)) { count2++; } } } if (count2 == row) { return '*'; } //判断电脑赢条件1 for (i = 0; i < row; i++) { for (j = 0; j < col; j++) { if (board[i][j] == '#' && i == j) { count5++; } } } if (count5 == row) { return '#'; } //判断玩家赢条件2 for (i = 0; i < row; i++) { if (board[i][k] == '*') { count4++; } k--; } if (count4 == row) { return '*'; } 判断电脑赢条件2 for (i = 0; i < row; i++) { if (board[i][k1] == '#') { count7++; } k1--; } if (count7 == row) { return '#'; } //判断玩家赢条件3 for (i = 0; i < row; i++) { int count = 0; for (j = 0; j < col; j++) { if (board[i][j] == '*') { count++; } } if (count == row) { return '*'; } } //判断电脑赢条件3 for (i = 0; i < row; i++) { int count = 0; for (j = 0; j < col; j++) { if (board[i][j] == '#') { count++; } } if (count == row) { return '#'; } } //判断玩家赢条件4 for (j = 0; j < col; j++) { int count1 = 0; for (i = 0; i < row; i++) { if (board[i][j] == '*') { count1++; } } if (count1 == col) { return '*'; } } //判断电脑赢条件4 for (j = 0; j < col; j++) { int count1 = 0; for (i = 0; i < row; i++) { if (board[i][j] == '#') { count1++; } } if (count1 == col) { return '#'; } } //判断平局 int count3 = 0; for (i = 0; i < row; i++) { for (j = 0; j < col; j++) { if (board[i][j] != ' ') count3++; } } if (count3 == (row*col)) return 'p'; else return 'c'; } void game() { char ret = 0; char board[ROW][COL] = { 0 }; Initboard(board, ROW, COL); Printboard(board,ROW,COL); while (1) { palyer_move(board, ROW, COL); //玩家落子 Printboard(board, ROW, COL); //每次落子后都需打印棋盘 if ((ret = Judge(board, ROW, COL))!='c') //这里进行判断游戏是否产生了结果需要结束，游戏结束有三种情况，1.玩家赢 2.电脑赢 3.平局，都不是继续游戏 { break; } computer_move(board, ROW, COL); //电脑落子 Printboard(board, ROW, COL); if ((ret = Judge(board, ROW, COL)) != 'c') { break; } } if (ret == '*') { printf("玩家赢！\n"); } else if (ret == '#') { printf("电脑赢！\n"); } else if (ret == 'p') { printf("平局！\n"); } } int main() { srand((unsigned int)time(NULL)); int input = 0; do { menu(); scanf("%d", &input); switch (input) { case 1: game(); break; case 0: break; default: printf("输入错误，请重新选择：\n"); break; } } while (input); system("pause"); return 0; }