医生一周排班显示 使用SQL语句使数据从坚向排列转化成横向排列排班表

    xiaoxiao2022-07-03  114

    [导读]Extract 属于 SQL 的 DML(即数据库管理语言)函数,同样,InterBase 也支持 Extract,它主要用于从一个日期或时间型的字段内抽取年、月、日、时、分、秒数据,因此,它支持其关健字 YEAR、MONTH、DAY、HOUR、MINUTE、SECOND、WEEKDAY、YEARDAY。

    知识重点:

    1.extract(day from schedule01::timestamp)=13

    Extract 属于 SQL 的 DML(即数据库管理语言)函数,同样,InterBase 也支持 Extract,它主要用于从一个日期或时间型的字段内抽取年、月、日、时、分、秒数据,因此,它支持其关健字 YEAR、MONTH、DAY、HOUR、MINUTE、SECOND、WEEKDAY、YEARDAY。

      Extract 的使用语法为:

       EXTRACT(关健字 FROM 日期或时间型字段)

      如:extract(year from schedule01)=2017从日期中提取年份

    2.max()函数:取最大值

    3.case()函数的嵌套

      注意嵌套case()函数时,每个case的开始和结束。 

     


     

    排班功能:现有两个人员(A和B),他们在不同日期的值班状态(state)不同,现在要查询他们在2017.6月的值班信息

    表结构如下:

    CREATE TABLE public.temp_schedule

    (

      id integer NOT NULL DEFAULT nextval('temp_schedule_id_seq'::regclass),

      schedule01 timestamp without time zone,--日期

      schedule03 character varying(255),--姓名

      state character varying(255),--值班状态(0休 1班)

      CONSTRAINT temp_schedule_pkey PRIMARY KEY (id)

    )

    1.查询SQL语句:

    select schedule03,schedule01,state  from temp_schedule

     where extract(year from schedule01)=2017 and extract(month from schedule01)=6

     order by  schedule03,schedule01;

    显示为:

     

     

    2.现在需要根据(6月的)日期,从1号开始根据人员名称横向合并排列数据(即只显示两行)

    显示效果如下:

    实现的SQL语句如下:

    select schedule03 as name

    ,max(case when extract(day from schedule01::timestamp)=1 then state end) as day1

    ,max(case when extract(day from schedule01::timestamp)=2 then state end) as day2

    ,max(case when extract(day from schedule01::timestamp)=3 then state end) as day3

    ,max(case when extract(day from schedule01::timestamp)=4 then state end) as day4

    ,max(case when extract(day from schedule01::timestamp)=5 then state end) as day5

    ,max(case when extract(day from schedule01::timestamp)=6 then state end) as day6

    ,max(case when extract(day from schedule01::timestamp)=7 then state end) as day7

    ,max(case when extract(day from schedule01::timestamp)=8 then state end) as day8

    ,max(case when extract(day from schedule01::timestamp)=9 then state end) as day9

    ,max(case when extract(day from schedule01::timestamp)=10 then state end) as day10

    ,max(case when extract(day from schedule01::timestamp)=11 then state end) as day11

    ,max(case when extract(day from schedule01::timestamp)=12 then state end) as day12

    ,max(case when extract(day from schedule01::timestamp)=13 then state end) as day13

    from temp_schedule

    where extract(year from schedule01)=2017 and extract(month from schedule01)=6

    group by schedule03;

     

    3.将人员的值班状态通过汉字(0休 1班)显示出来,显示效果如下:

    SQL语句(主要是实现case的嵌套):

    select schedule03 as name

    ,max(case when extract(day from schedule01::timestamp)=1 then (case when state='0' then '休' else '班' end) end) as day1

    ,max(case when extract(day from schedule01::timestamp)=2 then (case when state='0' then '休' else '班' end) end) as day2

    ,max(case when extract(day from schedule01::timestamp)=3 then (case when state='0' then '休' else '班' end) end) as day3

    ,max(case when extract(day from schedule01::timestamp)=4 then (case when state='0' then '休' else '班' end) end) as day4

    ,max(case when extract(day from schedule01::timestamp)=5 then (case when state='0' then '休' else '班' end) end) as day5

    ,max(case when extract(day from schedule01::timestamp)=6 then (case when state='0' then '休' else '班' end) end) as day6

    ,max(case when extract(day from schedule01::timestamp)=7 then (case when state='0' then '休' else '班' end) end) as day7

    ,max(case when extract(day from schedule01::timestamp)=8 then (case when state='0' then '休' else '班' end) end) as day8

    ,max(case when extract(day from schedule01::timestamp)=9 then (case when state='0' then '休' else '班' end) end) as day9

    ,max(case when extract(day from schedule01::timestamp)=10 then (case when state='0' then '休' else '班' end) end) as day10

    ,max(case when extract(day from schedule01::timestamp)=11 then (case when state='0' then '休' else '班' end) end) as day11

    ,max(case when extract(day from schedule01::timestamp)=12 then (case when state='0' then '休' else '班' end) end) as day12

    ,max(case when extract(day from schedule01::timestamp)=13 then (case when state='0' then '休' else '班' end) end) as day13

    from temp_schedule

    where extract(year from schedule01)=2017 and extract(month from schedule01)=6

    group by schedule03 ;

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