scala模式匹配错误

scala模式匹配涉及到泛型时, 如果A在运行时并不存在。这意味着，对于实例来讲，任何参数都将被编译成AnyRef

test("checkList"){ val a = List(1,2,3,5,6) val b = List("1","2") checkList(a) //List of Ints checkList(b) //List of Ints } def checkList[A](l: List[A]) = l match { case _:List[Int] => println("List of Ints") case _:List[String] => println("List of Strings") case _ => println("Something else") }

采用实验性的特性Manifest

def checkList[A](l: List[A])(implicit m: scala.reflect.Manifest[A]) = m.toString match { case "Int" => println("List of Ints") case "java.lang.String" => println("List of Strings") case _ => println("Something else") }